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Let n ≥ 2 be a natural number and 0 < θ < π/2. Then ∫ (sinn θ - sinθ)^1/n cosθ/(sin^n+1θ) dθ is equal to (where C is a constant of integration) -
Let n be a natural number such that 1/2+1/3+1/7+1/n is also a natural
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![Let n be a natural number and let a be a real number. The number of zeros of x^2n + 1 - ( 2n + 1 ) x + a = 0 in the interval [ - 1,1 ] is](https://i.ytimg.com/vi/-pcul7ZYmr0/maxresdefault.jpg "Let n be a natural number and let a be a real number. The number of zeros of x^2n + 1 - ( 2n + 1 ) x + a = 0 in the interval [ - 1,1 ] is")
Let n be a natural number and let a be a real number. The number of zeros of x^2n + 1 - ( 2n + 1 ) x + a = 0 in the interval [ - 1,1 ] is
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![Let n be a natural number and let a be a real number. The number of zeros of x^2n + 1 - ( 2n + 1 ) x + a = 0 in the interval [ - 1,1 ] is](https://d1hhj0t1vdqi7c.cloudfront.net/v1/LXBjdWw3WlltcjA=/sd/ "Let n be a natural number and let a be a real number. The number of zeros of x^2n + 1 - ( 2n + 1 ) x + a = 0 in the interval [ - 1,1 ] is")
Let n be a natural number and let a be a real number. The number of zeros of x^2n + 1 - ( 2n + 1 ) x + a = 0 in the interval [ - 1,1 ] is
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Let n be a natural number such that 1/2+1/3+1/7+1/n is also a natural
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